`I=int sqrt(1-x^(2))dx`

I=int sqrt((1+x)/(x))dx

" (i) "int sqrt(x^(2)-8)dx

I=int1/(sqrt(a-x))dx

If I=int x sqrt((x^(2)+1)/(x^(2)-1))dx ,then "I" equals

I=int(sqrt(x^2+1))/(x^(4))dx

Integration of certain irrational functions with the aid of trigonometric or hyperbolic substitutions I=int(sqrt(x^(2)+1))/(x^(2))dx.

Evaluate: (i) int sqrt((1+cos2x)/(2))dx (ii) int sqrt((1-cos2x)/(2))dx

(i) int 1/sqrt(4+x^2) dx (ii) int 1/sqrt(9+x^2) dx (iii) int 1/sqrt(1+4x^2) dx

"I=int(x)/(sqrt((1-x)))dx