Height & Distance

Class 10 Maths Ex 9.1 examples (Part 2) Ch 9 Some Applications of Trigonometry (Heights & Distances)

Application Of Trigonometry Class 10 | CBSE Class 10 Height And Distance

A body is thrown vertically upwards and takes 5 seconds to reach maximum height. The distance travelled by the body will be same in :-

In first second of an object dropped from some height, the distance by which it will fall is ("take g = 10 "ms"^(–2))

A ball is projected form ground with a speed of 20 ms^(-1) at an angle of 45∘ with horizontal.There is a wall of 25m height at a distance of 10m from the projection point. The ball will hit the wall at a height.

A statue of height 4 m stands on a tower of height 10 m. The angle subtended by the status at the eyes of an observer of height 2m, standing at a distance of 6m from base of the tower is

A particle just clears a wall of height b at distance a and strikes the ground at a distance c from the point of projection. The angle of projection is (1) tan^(-1)b/(a c) (2) "45"^o (3) tan^(-1)(b c)/(a(c-a) (4) tan^(-1)(b c)/a

PQ is a post of height a, AB is a tower of height h at a distance x from the post, and alpha and beta are the angles of elevation of B, at P and Q respectively such that alpha gt beta . Then

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t - 5t^(2))m . The velocity with which the projectile is projected is

A body freely falling from the rest has velocity v after it falls through a height h the distance it has to fall down for its velocity to become double is