Arrange Fe, `Fe^(3+)`,`Fe^(2+)` in increasing order of their atomic size.

(i) On the basis of the standard electrode potential values stated for acid solutions, predict whether Ti^(4+) species may be used to oxidise Fe(II) to Fe(III) {:(Ti^(4+) + e^(-) to Ti^(3+), E^(@) = +0.01V), (Fe^(3+) + e^(-) to Fe^(2+), E^(@)= +0.77V):} (ii) Based on the data arrange Fe^(3+), Mn^(2+) " and " Cr^(2+) in the increasing order of stability of +2 oxidation state. (Give a brief reason) E_(Cr^(3+)//Cr^(2+))^(@) = -0.4V E_(Mn^(3+)//Mn^(2+))^(@) = +1.5V E_(Fe^(3+)//Fe^(2+))^(@) = +0.8V

What would be the correct order if Zn, Fe, Al and Cu are arranged in increasing order of reactivity?

Arrange Na, Mg , Fe, Pb , Hg and Cu in order of decreasing reactivity.

In the electrochemical reaction, 2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+) , increasing the concentration of Fe^(2+) :

Out of Fe^(2+), Fe^(3 +), Mn^(2+) and Ti^(2+) the least size is of

Arrange in increasing order of oxidation number V_2O_5,CrO_3,MnO_2,Fe_2O_3

In the electrochemical reaction, 2Fe^(3+)+Zn rarr Zn^(2+) + 2Fe^(2+) increasing the concentration of Fe^(2+) :