मानव शरीर से जुड़े 10 रोचक तथ्य | 10 Facts About Human Body | Body Facts You Didn't Know | #shorts

A force vec(F) = (40 hat (i) + 10 hat(j)) N acts on body of mass 5 kg. If the body starts from rest, its position vector vec(r) at time t = 10 s, will be

When a bullet of mass 10 g and speed 100 m/s penetrates up to distance 1 cm in a human body at rest. The resistance offered by human body is :

A body is projected at time t = 0 from a certain point on a planet’s surface with a certain velocity at a certain angle with the planet’s surface (assumed horizontal). The horizontal and vertical displacements x and y (in meters) respectively vary with time t (in second) as x= 10 sqrt3t , y= 10t -t^2 What is the magnitude and direction of the velocity with which the body is projected ?

In the given figure F=10N, R=1m , mass of the body is 2kg and moment of inertia of the body about an axis passing through O and perpendicular to the plane of the body is 4kgm^(2) . O is the centre of mass of the body. If the ground is smooth, what is the total kinetic energy of the body after 2s ?

Given a = 2t + 5 . Calculate the velocity of the body after 10 sec if it starts from rest.

A body of mass 5 kg is acted on by a net force F which varies with time t as shown in graph Fig. Then the net momentum is SI units gained by the body at the end of 10 seconds is

A point on a body performing pure rotation is 10 cm from the axis of rotation of body. Angular position of the point from reference line is given by theta=0.5 e^(2t) , where theta is in Radian and t in second. The acceleration of the point at t=0 is

The radius of gyration of a body about an axis at a distance of 6 cm from the centre of mass is 10 cm. What is its radius of gyration about a parallel axis through its centre of mass?