`int _-1^1(1)/(x^(2)+2x+5)dx`

int_(1)^(5) (x^(2) -2x) dx

" %."int_(-1)^(1)(dx)/(x^(2)+2x+5)

int_(0)^(1)(1)/(x^(2)+4x+5)dx =

int(x-1)/(x^(2)-2x-5)dx

int (1) / (x ^ (2) + 2x + 5) dx

int ( x +2)/( 2x ^(2) + 6x + 5) dx = p int ( 4x +6)/( 2x ^(2) + 6x +5) dx + (1)/(2) int (1)/( 2x ^(2) + 6x + 5) dx then p

int_(-1)^(1) (dx) / (x^(2)+2x+5) is equal to

Evaluate: int_(1)^(2)(1)/((x+1)(x+2))dx( ii) int_(1)^(2)(1)/(x(1+x^(2)))dx

int_(-1)^(1)(x^(2)+x)/(x^(2)+1)dx=