10.0001+9.9999-8.9995=? (a) 9.0005 (b) 10.9995 (c) 11.0001 (d) 11.0005 (e) None of these
Let a,b,c,d be real numbers in G.P. If u,v,w satisfy the system of equations u+2y+3w=6,4u+5v+6w=12 and 6u+9v=4 then show that the roots of the equation ((1)/(u)+(1)/(v)(+)/(w))x^(2)+[(b-c)^(2)+(c-a)^(2)+(d-b)^(2)]x+u+v+w=0 and 20x^^2+10(a-d)^^2x-9=0 ' are reciprocals of each other.
0.0001 is equivalent to a) 0.1% b) 0.01% c) 0.0001% d) 0.001%
If x = "log"_(0.1) 0.001, y = "log"_(9) 81 , then sqrt(x - 2sqrt(y)) is equal to
If x=log_(0.1)0.001,y=log_(9)81, then sqrt(x-2sqrt(y))=
In the mirror formula, (1)/(f)=(1)/(v)+1/u,f does not change when u is changed.
Let a,b,c and d are real numbers in GP. Suppose u,v,w satisfy the system of equations u+2y+3w=6,4u+5y+6w=12 and 6u+9v=4 . Further consider the expressions f(x)=(1/u+1/v+1/w)x^(2)+[(b-c)^(2)+(c-a)^(2)+(x-b)^(2)] x+u+v+w=0 and g(x)=20x^(2)+10(a-d)^(2)x-9=0 (u+v+w) is equal to
How will you code INDEPENDENCE if R and U are coded as 9 and 6 respectively ?
If U={4,5,6,7,8,9,10,11,12} and C={4,6,8,10,12 } then find U-C .
