If `PCl_5` is 80 dissociated at 250 degree celsius then its vapour density at room temperature will be​

When PCl_(5) is heated, it dissociates into PCl_(3) and Cl_(2) . The vapour density of the gas mixture at 200^(@)C and at 250^(@)C is 70 and 58 , respectively. Find the degree dissociation at two temperatures.

During thermal dissociation of a gas, the vapour density.

The rate of cooling of a substance in moving air is proportional to the difference of temperatures of the substance and the air. A substance cools from 36 degree celsius to 34 degree celsius in 15 minutes. Find when the substance will have the temperature 32 degree celsius , it being known that the constant temperature of air is 30 degree celsius.

At some temperature and under a pressure of 4 atm, PCl_(5) is 10% dissociated. Calculated the pressure at which PCl_(5) will be 20% dissociated temperature remaining same.

For the dissociation of PCl_(5) into PCl_(3) and Cl_(2) in gaseous phase reaction , if d is the observed vapour density and D the theoretical vapour density with 'alpha' as degree of dissociation ,variaton of D/d with 'alpha' is given by ?