Two grams of dihydrogen diffuse from a container in 10 minutes. How many gram of dioxygen would diffuse through the same container in thhe same time under similar conditions?

The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion prop (1)/(sqrt(d)) If r_(1) and r_(2) represent the rates of diffusion of two gases and d_(1) and d_(2) are their respective densities, then r_(1)/(r_(2))=sqrt((d_(2))/(d_(1))) r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2)) (V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1))) V prop n (where n is no of moles) V_(1) prop n_(1) and V_(2) prop n_(2) 2 g of hydrogen diffuse from a container in 10 minutes How many grams of oxygen would diffuse through the same container in the same time under similar conditions ? .

2 grams of Helium diffuses from a porous plate in "4" min.How many grams of CH_(4) would diffuse through the same plate in same time under similar conditions? (A) "4g (B) 16g (C) 8g (D) 2g

4 gm of sulphur dioxide gas diffuses from a container in 8 min. Mass of helium gas diffusing from the same container over the same time interval is :

300 mL of nitrogen gas diffuse througha a porous memebrane in 100 seconds. How long will it take for 400 mL of CO_(2) to diffuse through the same membrane under similar conditions of temperature and pressure ?

50 mL of hydrogen diffuses through a small hole from vessel in 20 minutes time. Time taken for 4 mL of oxygen to diffuse out under similar conditions will be

50 mL of hydrogen diffuse through a small hole from a vessel in 20 mintues time. Time taken for 40 ml of oxygen to diffuse out under similar conditions will be :