24 g of He diffused in 5 sec. find the mass of `O_2` diffused in 10 sec​

100 mL of H_(2) gas diffues in 10 sec. X mL of O_(2) gas diffuses in t sec. X and t cannot be

The Graham's law states that ''at constant pressure and temperature the rate of diffusion or effusion of a gas is inversely proportional to the squar root of its density Rate of diffusion prop (1)/(sqrt(d)) If r_(1) and r_(2) represent the rates of diffusion of two gases and d_(1) and d_(2) are their respective densities, then r_(1)/(r_(2))=sqrt((d_(2))/(d_(1))) r_(1)/(r_(2)) =sqrt((M_(2))/(M_(1))) xx P_(1)/(P_(2)) (V_(1)xxt_(2))/(V_(2)xxt_(1)) = sqrt((d_(2))/(d_(1))) = sqrt((M_(2))/(M_(1))) V prop n (where n is no of moles) V_(1) prop n_(1) and V_(2) prop n_(2) If some moles of O_(2) diffuse in 18 sec and same moles of other gas diffuse in 45sec then what is the molecular weight of the unknown gas ? .

100 mL O_(2) gas diffuses in 10 sec. 100 mL of gas X diffuses in t sec. Gas X and time t can be

24 mL H_(2) , diffuses in 100 s. How much volume of SO_(2) , will diffuse during the same time?

360cm of CH_(4) gas diffused through porous membrane in 15 minutes,under similar conditions, 120cm^(3) of another gas diffused in 10 minutes.Find the molar mass of the gas.