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For the cell, Pb (s)l Pb^(2+)(1M) llAg^+...

For the cell, Pb (s)l `Pb^(2+)`(1M) ll`Ag^+`(1M) lAg (s)`, if concentration of an ion in the anode compartment is increased by a factor of 10, the emf of the cell will​

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The Nernst equation: Consider the following galvanic cell Pb(s) | Pb^(2+)(aq.) || Ag^(2+)(aq.) | Ag(s) (a) What is the quantitative change in the cell voltage on increas-ing the ion concentrations in the anode compartment by a factor of 10 ? (b) What is the quantitative change in the cell voltage on increas-ing the ion concentration in the cathode compartment by a factor of 10 Strategy: The conventional notation of the cell tells us that lead is the anode while silve is the cathode. Therfore, the cell reaction is Pb(s) + 2Ag^(+)(aq.) rarr Pb^(2+)(aq.) + 2Ag(s) The cell potantial (at 25^(@)C ) is given by the Nernst equation, where n = 2 and Q = C_(Pb^(2+))//C_(Ag^(+)) : E_("cell") = E_("cell")^(@)-(0.0592 V)/(n) "logQ" E_("cell")^(@)-(0.0592 V)/(n) "logQ" C_(Pb^(2+))/C_(Ag^(+))^(2)

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In the cell represented by Pb(s)|Pb^(2+)(1 M)||Ag^(+)(1M)|Ag(s) the reducing agent is

Consider the following Galvanic cell:- By what value the cell voltage when concentration of ions in anodic and cathodic compartments both increased by factor of 10 at 298K:

In the Daniel cell, if the concentrations of Zn^(2+) and Cu^(2+) ions are doubled at 298 K , the e.m.f. Of the cell __________.

What will happen to the value of emf of the following cell if the cencentration of the electrolyte in the anode compartment is increased ? Zn | Zn^(2+)(0.1 M)||Cu^(2+)(0.1 M) Cu .

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