The position vector of a particle is given by `vecr=(3t^(2)hati+4t^(2)hatj+7hatk)m` at a given time `t`.The net displacement of the particle after `10 s` is

The position vector of a moving particle at seconds in given by vecr=3hati+4t^(2)hatj-t^(3)hatk .Its displacement during an interval of 1s to 3s is

The position vector of a particle is given by vecr=(2 sin 2t)hati+(3+ cos 2t)hatj+(8t)hatk . Determine its velocity and acceleration at t=pi//3 .

The position of a particel is expressed as vecr = ( 4t^(2)hati + 2thatj) m. where t is time in second. Find the acceleration of the particle.

The position vector of a particle is given by vec r = (2t hati+5t^(2)hatj)m (t is time in sec). Then the angle between initial velocity and initial acceleration is

The position of an object is given by vecr= ( 9 thati + 4t^(3)hatj) m. find its velocity at time t= 1s.

The positione of a particle is expressed as vecr = ( 4t^(2) hati + 2thatj) m, where t is time in second. Find the velocity o the particle at t = 3 s

The position vector of a particle is determined by the expression vecr=2t^(2) hati+ 3thatj + 9hatk . The magnitude of its displacement ( in m) in first two seconds is

The position of a particle is given by vecr = 2t^(2) hati + 3t hatj + 4hatk where t is in second and the coefficients have proper units for vecr to be in metre. The veca(t) of the particle at t = 1 s is

The position of a particle is given by vecr = 3t hati + 2t^(2) hatj + 5hatk , where t is in seconds and the coefficients have the proper units for vecr to be in metres. The direction of velocity of the particle at t = 1 s is

The position vector of a aprticle is given as vecr=(t^2-4t+6)hati+(t^2)hatj . The time after which the velocity vector and acceleration vector becomes perpendicular to each other is equal to