A force `F=(2thati+3t^(2)hatj)`N acts on an object moving in XY-plane. Find the magnitude of change in momentum of the object in the time interval t=0 to t=2s.

Find average speed in time interval t= 2 to t=10s

Two forces of mangitude F_(1) and F_(2) are acting on an object.The magnitude of the net force F_(n e t ) on the object will be in the range.

Velocity of a particle of mass 2kg varies with time t according to the equation vec(v)=(2thati+4hatj) m//s . Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

Velocity of particle of mass 2kg varies with time t accoridng to the equation vecv=(2thati+4hatj)ms^(-1) . Here t is in seconds. Find the impulse imparted to the particle in the time interval from t=0 to t=2s.

The velocity-time graph of an object moving along a straight line is as shown in Fig. 3.37. Find the net distance covered by the object in time interval between t=0 to t=10s. Also find the displacement in time 0 to 10 s.

A particle is moving along the x-axis such that s=6t-t^(2) , where s in meters and t is in second. Find the displacement and distance traveled by the particle during time interval t=0 to t=5 s .

An object moves along x-axis such that its position varies with time according to the relation x=50t-5t^(2) Here, x is in meters and time is in seconds. Find the displacement and distance travelled for the time interval t = 0 to t = 6 s.

A force F=(3thati + 5hatj)N acts on a body due to which its displacement varies as S=(2t^(2)hat-5hatj)m . Work done by these force in 2 s is .

The displacement of a body of mass 2kg varies as S=t^(2)+2t .Where S is in meters and t is in second.The work done by all the forces acting on the body during the time interval t=0 to t=3s is ?

Calculate impulse of force vecF=(3t^2hati-(2t-1)hatj+2hatk)N over the time interval from t=1s to t=3s.