Dimensions of ` sin theta ` is

In the expression y = a sin (omega t + theta ) , y is the displacement and t is the time . Write the dimension of a , omega and theta .

(sin3 theta-sin theta * sin ^ (2) (2 theta)) / (sin theta + sin2 theta * cos theta) = cos x rarr x =

sin theta + sin3 theta + sin5 theta = 0

Prove each of the following identities : (i) (sin theta - cos theta)/(sin theta + cos theta) + ( sin theta+ cos theta)/(sin theta - cos theta) = (2)/((2 sin^(2) theta -1)) (ii) (sin theta + cos theta ) /(sin theta - cos theta) + ( sin theta - cos theta) /(sin theta + cos theta) = (2) /((1- 2 cos^(2) theta))

If : 0 lt theta lt pi/2 and sin 7theta + sin 4 theta + sin theta=0 , then : theta =

The value of (sin^3 theta + cos^3 theta)/(sin theta+ costheta)+((cos^3 theta - sin^3 theta))/(cos theta - sin theta) is

(sin5 theta-2sin3 theta + sin theta) / (cos5 theta-cos theta) = tan theta

sin 4 theta + 2 sin 8 theta + sin 12 theta = ?

Prove that: sqrt((1+ sin theta)/(1 - sin theta)) - sec theta = sec theta - sqrt((1 -sin theta)/(1 + sin theta))

Solve 4sin theta sin2 theta sin4 theta=sin3 theta