What is the product of permeability of free space and permittivity of free space?

The speed of light in vacuum, c, depends on two fundamental constants, the permeability of free space, mu_(0) and the permittivity of free space, epsilon_(0) . The speed of light is given by c=(1)/(sqrt(mu_(0)epsilon_(0))) . The units for mu_(0) are

Assertion : The quantities (1sqrt(mu_(0) epsilon_(0))) is dimensionally equal to velocity and numericallyy equal of light. Reason : mu_(0) is permeability of free space and epsilon_(0) is the permittivity of free space.

Assertion: the quantity (1//sqrt(mu_(0) epsilon_(0))) is dimensionally equal to velocity and numerical equal to velocity of light. Reason : mu_(0) is permeability of free space and epsilon_(0) is the permitivity of free space.

Which of the following does not have the dimensions of velocity ? ( Given epsilon_(0) is the permittivity of free space , mu_(0) is the permittivity of free space , v is frequency , lambda is wavelength , P is the pressure , and rho is density , k is wave number , omega is the the angular frequency)

The dimensions of permeability of free space can be given by

The value of electric permittivity of free space is

SI unit of in_(0) (permittivity of free space) is: