What is the value of the shunt resistance that allows 20% of the main current through a galvanometer of `90 ohm `

What is the value of the shunt that passes 10% of the main current through a galvenomenter of 99 Omega ?

The resistance of the shunt required to allow 2% of the main current through the galvanometer of resistance 49Omega is

If a galvanometer is shunted by (1/n)th of the value of its resistance, then the fraction of the total current passing through the galvanometer is

The value of shunt to be used to pass 1//10th of the total current through a galvanometer of resistance 100Omega is

A galvanomter of resistance 50Omega is shunted by a resistance of 5Omega . What fraction of the main current passes through the galvanometer? Through the shunt?

A galvanometer of resistance 100ohms is shunted so that only 1//11 of the main current flows through the galvanometer. The resistance of the shunt is

A galvanometer of resistance 20Omega is shunted by a 2 Omega resistor. What part of the main current flows through the galvanometer ?

When a galvanometer of resistance G is shunted with a low resistance S, then the effective resistance R_(eff) of galvanometer becomes R_(eff)=(GS)/(G+S) If current is passed through such a galvanometer, then the major amount of current flows through shunt and the rest through galvanometer, i.e., the current divides itself in the inverse ratio of resistance. Read the above passage and answer the following questions: (i) Why is the resistance of shunted galvanometer lower than that of shunt? (ii) A galvanometer of resistance 30Omega is shunted by a resistance of 3Omega . What fraction of the main current passes (i) through the galvanometer and (ii) through the shunt? (iii) What are the basic values you learn from the above study?

Calculate the value of the shunt resistance when connected across a galvanometer of resistance 18Omega will allow 1/10 th of the current to pass through the galvanometer.