A phase difference π between two interfering beams is equivalent to the path difference​

Maximum intensity in YDSE is I_0 . Find the intensity at a point on the screen where (a) The phase difference between the two interfering beams is pi/3. (b) the path difference between them is lambda/4 .

If path difference between two interfering waves is zero, then the point will be

The path difference between two waves is

The path difference between two interfering waves of equal intensities at a point on the screen is lambda//4 . The ratio of intensity at this point and that at the central fringe will be

Phase difference between any two points of a wavefront is

Phase Difference Of Two Shm

The relationship between phase difference Deltaphi and the path difference Deltar between two interfering waves is given by: ( lambda = wavelength)

If path difference between two interfering waves arriving at a point is zero, then the point will

If the path difference between the interfering waves is n lambda , then the fringes obtained on the screen will be

In the Young's double slit experiment, if the phase difference between the two waves interfering at a point is phi , the intensity at that point can be expressed by the expression