10g water at 80 degree is mixed with 50g copper at 10 degree .find temperature of mixture heat capacity of water =4.2 j/gc ,copper=0.4 j/gc

100g of ice at 0C is mixed with 100g of water 80C The final temperature of the mixture will be

10 g ice at 0^(@)C is mixed with 20 g of water at 20^(@)C . What is the temperature of mixture?

540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is

10 g of ice at 0^@C is mixed with 100 g of water at 50^@C . What is the resultant temperature of mixture

If 2g ice at 0^(0)C is dropped into 10g water at 80^(0)C then temperature of mixture is

If 10 g of the ice at 0^@C is mixed with 10g of water at 100^@ C , then the final temperature of the mixture will be

10 g of water at 70^@C is mixed with 5 g of water at 30^@C . Find the temperature of the mixture in equilibrium. Specific heat of water is 1 cal//g-^@C .

100 g of ice at 0^(@)C is mixed with 100 of water 80^(@)C . The final temperature of the mixture will be