`ABCDEF` is a regular hexagon prove that `AB + AC + AD + AE + AF = 6AO`

If ABCDEF is a regular hexagon, prove that AD+EB+FC=4AB .

If ABCDEF is a regular hexagon, then Delta ACE is

In a regular hexagon ABCDEF,vec AE

In the adjoining figure, ABCDEF is a regular hexagon. Prove that squareABDE, square ACDF and squareAGDH are parallelograms.

If ABCDEF is a regular hexagon, prove that vec(AC)+vec(AD)+vec(EA)+vec(FA)=3vec(AB)

In Fig. ABCDEF is a ragular hexagon. Prove that vec(AB) +vec(AC) +vec(AD) +vec(AE) +vec(AF) = 6 vec(AO) .

If ABCDEF is a regular hexagon , then bar(AB) + bar(AC) + bar(AE) + bar(AF) =