Find the radius of curvature at `x = pi/2` to the curve `y = 4sinx - sin2x`​

The radius of curvature of the curve y^2=4x at the point (1, 2) is

Find the equation of the tangent line to the curve y=sinx" at "x=(pi)/(4).

Find the equation of the tangent at t=(pi)/(4) to the curve : x=sin 3t, y = cos 2t.

Find the equation of the tangent to the curve y=x-sin x cos x at x=(pi)/(2)

Find the equations of the tangent and normal to the curve x = a sin 3t, y = cos 2 t " at " t = (pi)/(4)

Find the area of the region bounded by the curve y = sinx , the lines x = - ( pi ) /(2), x = ( pi ) /(2) and X- axis.

Find the coodinates of the point of intersection of the curves y= cos x , y= sin 3x if -(pi)/(2) le x le (pi)/(2)

Find the equation of the normal to the curve y = (sin 2x + cot x + 2)^(2) " at " x = (pi)/(2)

Find the equation of the normal to the curve y = 2 sin^(2) 3x "at " x = (pi)/(6)