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2/5*13*3/5*13-10 =...

`2/5*13*3/5*13-10` =

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The line of intersection of the planes vecr.(3hati-hatj+hatk)=1 and vecr.(hati+4hatj-2hatk)=2, is (A) (x-6/13)/2=(y-5/13)/-7=z/-13 (B) (x-6/13)/2=(y-5/13)/7=z/-13 (C) (x-4/7)/-2=y/7=(z-5/7)/13 (D) (x-4/7)/-2=y/-7=(z+5/7)/13

A=[[1,2,-12,3,-13,4,-1]] and B=[[1,-3,-5-1,3,-5-1,3,-5]]

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