4 women & 6 men have to be seated in a row given that no two women can sit together. how many different arrangements are there

m men and w women are to be seated in a row so that no two women sit together.If m>w then the number of ways in which they can be seated is

5 men and 6 women have to be seated in a straight row so that no two women are together. Find the number of ways this can be done.

m men and n women are to be seated in a row so that no two women sit together.If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!)

m women and n men are too be seated in a row so that no two men sit together. If mgtn then show that the number of wys in which they can be seated is (m!(m+1)!)/((m-n+1)!)