If `24 . 125 = 24+ a/10 +b/100 + c/1000` then find `a+b+c`

If 24.125=24+(A)/(10)+(B)/(100)+(C)/(1000), then A+B+C=3( b) 613(d)8

If a+b=10, ab=24 then find a^2+b^2

For real a, b and c if a^(2) + b^(2) + c^(2) = ab + bc + ca , then find the value of (a + b + c)^(2) A. 9a^(2) B. 81 a^(2) C. 27 a^(2) D. 24 a^(2)

If a = 16, b = 24 and c = 20, then the value of cos(B/2)=

If log_(10) 2 = 0.3010 and log_(10) 3 = 0.477 , then find the number of digits in the following numbers: (a) 3^(40)" "(b) 2^(22) xx 5^(25)" (c) 24^(24)

If log_(10) x+log_(10) y= 3 and log_(10) x-log_(10) y=1, then x and y are respectively a. 10 and 100 b. 100 and 10 c. 1000 and 100 d. 100 and 1000

If a = 24, b = 26, c = 28 , then the value of a^2 + b^2 + c^2 - ab - bc - ac will be

If a^(2)+b^(2)+c^(2)=24 and ab+bc+ca=-4, then find a+b+c