solve `( - p + 4q - 3r ) ^ 2`

Add: 6p + 4q - r + 3, 3r - 5p - 6, 11q - 7p + 2r - 1 and 2q - 3r + 4

If 3 - 4i is a root of x^(2) - px + q = 0 where p, q in R . then value (2 p - q)/( p + q) is

Subtract : 4p^(2) + 5q^(2) - 6r^(2) + 7 from 3p^(2) - 4q^(2) - 5r^(2) - 6

If p : q = 3 : 4 and q : r = 8 : 9 , then p : r is equal to

Multiply the - 7p q ^(2) r ^(3), 12 p ^(2) q ^(2) r

If p = -2, q = - 1 and r = 3, find the value of (i) p^(2) + q^(2) - r^(2) (ii) 2p^(2) - q^(2) + 3r^(2) (iii) p - q - r (iv) p^(3) + q^(3) + r^(3) + 3 pqr (v) 3p^(2) q + 5pq^(2) + 2 pqr (vi) p^(4) + q^(4) - r^(4)

(3q + 7 p^(2) - 2r^(3) + 4) - (4 p^(2) - 2q + 7r^(3) - 3) = ?