`4a^2 + 12 a b + 9 b^2 - 8 a - 12 b` . Factor this equation

Find the product (2a + 3b - 4c) (4a ^(2) + 9b ^(2) + 16 c ^(2) - 6 ab + 12 bc +8 ca)

The factors of 625 a ^(12) - 81 b ^(12) are :

If 4x ^(2) + 12 xy - 8x + 9 y ^(2) - 12 y = (ax + by) (ax+ by -4), then the value of a ^(2) +b ^(2) is

Subtract the sum of 12ab-10b^2 -18a^2 and 9ab + 12 b^2+ 14a^2 " from the sum of " ab + 2b^2 and 3b^2-a^2 .

If 2 is a root of the equation x^2+b x+12=0 and the equation x^2+b x+q=0 has equal roots, then q= (a) 8 (b) -8 (c) 16 (d) -16

(a) Factorize a^(2) - (b -8) a - 8b