A semicircular sheet of paper of diameter 14 cm is bent to form an open conical cup. Find the capacity of the cup.

A semicircular sheet of diameter 28 cm is bent to form an open conical cup. Find the capacity of the cup. (Use sqrt3 = 1.732 )

A semi-circular sheet of metal of diameter 28cm is bent into an open conical cup.Find the depth and capacity of cup.

A semi-circular sheet of metal of diameter 28 cm is bent into an open conical cup. The depth of the cup is approximately

A semicircular sheet of paper of diameter 28cm is bent to cover the exterior surface of an open conical ice-cream cup.The depth of the ice-cream cup is (a) 8.12cm (b) 10.12cm (c) 12.12cm (d) 14.12cm

The side of a square metal sheet is 14 cm. A circular sheet of greatest diameter is cut out from it and removed. Find the area of the remaining metal sheet. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Area of circular sheet =pir^(2)=(22)/(7)xx7xx7=154cm^(2) Area of square metal sheet = ("side")^(2)=(14)^(2)=196cm^(2) (B) Since the circular sheet has greatest diameter, diameter of the circle = side of the square = 14 cm. (C) therefore "Radius of the circle sjeet"=(14)/(2)=7cm (D) therefore "The area of the remaining metal sheet"="Area of the square metal sheet"-"Area of the circular sheet"=196-154=42cm^(2)

From the four corners of a rectangular cardboard 38 cm xx 26 cm square pieces of size 3 cm are cut and the remaining cardboard is used to form an open box. Find the capacity of the box formed.

If the radii of the circular ends of a conical bucket which is 45 cm high be 28 cm and 7 cm, find the capacity of the bucket. (Use pi=22//7 )

A circular wire of diameter 42cm is bent in the form of a rectangle whose sides are in the ratio 6:5. Find the area of the rectangle.

A drinking glass is in the shape of a frustum of a cone of height 14cm. The diameters of its two circular ends are 4cm and 2cm. Find the capacity of the glass.