If `S = 60 + 2t – 10 t^2` is the displacement of the particle at time `t` , then find velocity at any time `t` .​

If displacement S at time t is S=10t-5t^(2) , then velocity at time t is

If the displacement of a particle is x=t^(3)-4t^(2)-5t , then the velocity of particle at t=2 is

If displacement S at time t is S=2t^(3) +6t , then velocity is always

The velocity of a particle is zero at time t = 2s, then

If displacement S at time t is S=-t^(3)+3t^(2)+5 , then velocity at time t=2 sec is

If displacements of a particle varies with time t as s = 1/t^(2) , then.

If displacement of particle is s=t^(3)-6t^(2)+9t+15, then velocity of the particle at beginning is

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The acceleration of a particle moving along a straight line is (6t^(2)-3t)cm/s^(2), at time t seconds,If the velocity of the particle at time 2 seconds be 10cm/s ,find its veloctiy at time t seconds.

The displacement of a particle at time t is x, where x=t^4-kt^3 . IF the velocity of the particle at time t=2 is minimum, then