If the mean of frequency distribution is 7.5 and ∑fi xi = 120 + 3k, ∑fi = 30, then k is equal to​: (a) `40` (b) `35` (c) `50` (d) `45`​

If the mean of a frequency distribution is 8.1 and sumf_i x_i=132+5k ,\ \ sumf_i=20 , then k= (a) 3 (b) 4 (c) 5 (d) 6

In a triangle A B C , if B=30^0a n d\ c=sqrt(3)\ b , then A can be equal to 45^0 (b) 60^0 (c) 90^0 (d) 120^0

If the median of the following frequency distribution is 28.5 find the missing frequencies: Class interval: 0-10 10-20 20-30 30-40 40-50 50-60 Total Frequency: 5 f_1 20 15 f_2 5 60

The sum of two integers is -35 . If one of them is 40, then the other is (a)5 (b) -75 (c) 75 (d) -5

If the mean of the following data is 18.75. Find the value of p . x_i : 10 15 p 25 30 f_i : 5 10 7 8 2

The mean of a discrete frequency distribution x_i//f_i ; i=1,\ 2,\ ddot,\ n is given by (a) (sumf_i x_i)/(sumf_i) (b) 1/n\ sum_(i=1)^nf_i x_i (c) (sumi=1nf_i x_i)/(sumi=1n x_i) (d) (sumi=1nf_i x_i)/(sumi=1n i)

The mean of the following frequency distribution is 62.8 and the sum of all the frequencies is 50. Compute the missing frequency f_1 and f_2 . Class: 0-20 20-40 40-60 60-80 80-100 100-120 Frequency: 5 f_1 10 f_2 7 8

Find the mean of the following frequency distributions: Class interval: 0-10 10-20 20-30 30-40 40-50 Frequency: 9 12 15 10 14

Find the mean deviation about the median for the data : x_i 15 21 27 30 35 f_i 3 5 6 7 8

Find the mean from the following frequency distribution of marks at a test in statistics: Marks (x) : 5 10 15 20 25 30 35 40 45 50 No. of students (f) : 15 50 80 76 72 45 39 9 8 6