`(-1) xx (-1) xx (-1) xx .....(2m+1)` times where m is a natural number is equal to

How many xx '5' appears in natural numbers between 1to 1000.

The set (0,2,6,12,20) in the set-builder form is (1) {x:x=n^(2)-3n+2," where "n'" is a natural number "&1 (2) {x:x=n^(2)-3n+2," where "'n'" is a natural number "&1 (3) {x:x=n^(2)-3n+4," where "'n'" is a natural number "&1 (4) {x:x=n^(2)+5n-6," where 'n' is a natural number "&1<=n<=5}

If 3(1)/2 xx 3(1)/2 =1(1)/3 xx _____ then the number in blank space is