From the sum of `2x^2 + 3xy - 5 and 7 + 2xy - x^2` subtract `3xy + x^2 - 2`

The sum of x^4 – xy + 2y^2 and -x^4 + xy + 2y^2 is

Subtract the sum of 7x^(2) - 4y^(2) " and " 4x^(2) + 3xy - 4y^(2) from the sum of 5x^(2) - 3xy - y^(2) "and " x^(2) + 2xy - 2y^(2) .

If 4x - 3y = 7xy and 3x + 2y = 18xy , then (x,y) =

Solve (9x ^(2) + 8 xy - 4) - ( 7x ^(2) - 2xy + 2).

Add : 5x ^(2) - 3xy + 4y ^(2) - 9, 7y ^(2)+ 5xy - 2x ^(2) + 13

Add: 4x^(2) - 7xy + 4y^(2) - 3, 5 + 6y^(2) - 8xy + x^(2) and 6 - 2xy + 2x^(2) - 5y^(2)

What should be subtracted from 2x^3 - 3x^2y + 2xy^2 + 3y^3 " to get " x^3- 2x^2y + 3xy^2 + 4y^3 ?

Solve (9xy + 7 xy + 9x ^(2)) + ( 8 + x ^(2) - xy - y ^(2) + 1).