The position of a particle varies with function of time as `y=(4sin t+3cos t)m`. Then the maximum displacement of the particle from origin will be

If the position of a particle along Y axis is represented as a funtion of time t by the equation y(t)=t^(3) then find displacement of the particle during the period t to t+Deltat

If the displacement of a particle varies with time as sqrt x = t+ 3

The position x of a particle varies with time t as X=at^(2)-bt^(3).The acceleration of the particle will be zero at time (t) equal to

The position x of a particle varies with time t as x=at^(2)-bt^(3) .The acceleration of the particle will be zero at time t equal to

The position x of a particle varies with time t as x=At^(2)-Bt^(3) .the acceleration at time t of the particle will be equal to zero

The displacement x is in centimeter of an oscillating particle varies with time t in seconds as x = 2 cos [0.05pi t+(pi//3)] . Then the magnitude of the maximum acceleration of the particle will be

The displacement of a particle executing S.H.M. is given by y = 0.25 sin 200t cm. The maximum speed of the particle is

Velocity of a particle varies with time as v=4t. Calculate the displacement of particle between t=2 to t=4 sec.

The position "x" of a particle varies with time (t) as x=At^(2)-Bt^(3)" .the acceleration at time t of the particle will be equal to zero

The position x of a particle varies with time t as x=at^(2)-bt^(3) . The acceleration at time t of the particle will be equal to zero, where (t) is equal to .