A particle is performing SHM, its velocity with respect to time is `V=30sin2 pi t`, then position of particle at `t=2sec` is

A particle performing S.H.M., its velocity when the particle moves from mean to extreme position is

A particle is performing SHM. Its kinetic energy K varies with time t as shown in the figure. Then

If the velocity of a particle moving along x-axis is given as v=(3t^(2)-2t) and t=0, x=0 then calculate position of the particle at t=2sec.

A particle executing SHM along y-axis, which is described by y = 10 "sin"(pi t)/(4) , phase of particle at t =2s is

A particle performing SHM is found at its eqilbrium at t=1 sec .and it is found to have a speed of 0.25 m//s at t=2sec . If the period of oscillation is 6sec . Calculate amplitude of oscillation-

Power supplied to a particle of mass 2kg varies with time as P=3t^(2)/2 watt,where t is in seconds If velocity of particle at t=0 is v=0 the velocity of particle at t=2 sec will be ?

A particle is performing SHM with time period T. The time after which KE and PE of particle will be equal is T/x then value of x is: (Consider t = 0 particle is at mean position and U = 0)

A particle performing S.H.M. about equilibrium position. Then the velocity of the particle is

A particle is in SHM with time period 3 sec. Calculate the displacement of particle from mean position after t = 0.5 sec.