find the value of `(x+y)^2+(x-y)^2`

If x^(2)-y^(2) =1 , (x gt y) ,then find the value of log(x-y) (x+y)

If x = cosecA + cosA and y = cosecA - cosA, then find the value of (2/(x+y))^2 +((x-y)/2)^2 -1 . यदि x = cosecA + cosA और y =cosecA - cosA, तो (2/(x+y))^2 +((x-y)/2)^2 -1 का मान ज्ञात करें:

If (2x-y) : (5x+3y) = 3:8, then find the value of (x^2+y^2) : (x^2-y^2) . यदि (2x-y) : (5x+3y) = 3:8 है, तो (x^2+y^2) : (x^2-y^2) का मान ज्ञात करें |

If x^2+y^2+1/y^2+1/y^2=4 then find the value of x^2+y^2

If x=(sqrt5+sqrt2)/(sqrt5-sqrt2) and y=(sqrt5-sqrt2)/(sqrt5+sqrt2) then find the value of (3x-2y)(x+2y)

If x^(2) - y^(2) = 1, (x gt y) then find the value of log_(x-y) (x+y)

If x^(2) + y^(2) -3xy = 0 and x gt y then find the value of log_(xy)(x-y) .

If ((2x-y)/(x+2y))=(1)/(2), then find the value of ((3x-y)/(3x+y))