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Class 10 ncert maths solution exercise 8.1 Qn o. 1

In the real numbers, what is the solution of the equation 4^(x+2)=8^(2x-1) ?

If the replacement set is the real numbers (R ), find the solution set of : 8 + 3x ge 28 - 2x .

If the system of linear equations x_1+2x_2+3x_3=6,\ x_1+3x_2+5x_3=9,\ 2x_2+5x_2+a x_3=b is consistent and has infinite number of solutions, then- a in R-{8}a n d\ b in R-{15} a=8,\ b can be any real number a=8,\ b=15 b=15 ,\ a can be any real number

The solution of an equation is x = 8 a. Form one or more linear equations in terms of x. b.Write one or more real - life situations , which can be written as linear equations , each of which has the given solution.

For the equation 40/[x-1]-160/[x-4]-200/[x-5]+320/[x-8]=6x^2-27x (A) Number of real solutions of above equation is 3 (B) If E denotes the product of non-zero real or complex roots of the equation, then sum of divisors of E is 2904 (C) If S denotes the set of all real roots of the equation then, sum of elements of S taken two at a time is 81 (D) If alpha_1,alpha_2 in R be two roots of the equation such that log_[alpha_2](2alpha_1) is defined then it must be 1.

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