CDP+TEACHING Apptitute

In the given figure CDP is a straight line Delta AQD is an equilateral triangle /_BAR=90^(@),/_QAR=135^(@),/_BCD=106^(@) and /_ABC=100^(@) . Then, /_PDQ equals

In Figure,ABCD and P is any point shown in the figure.Prove that: /_ABP+/_BPD+/_CDP=360^(@)

In Figure,lines AB and CD are parallel and P is any point between the two lines.Prove that /_ABP+/_CDP=/_DPB

The main teaching activity that takes place in preactive stage of teaching is