`(4)/(3)x+2y=8;2x+3y=12`

(3) x+2y=-1;2x-3y=12

3x+2y=8 2x-3y=8

3x+2y=8 2x-3y=1

Find the values of (x-y) , if (i) 3x + 4y = 11 , 4x + 3y = 10 (ii) 3x + 2y = 8 , 2x + 3y = 7

x^2+y^2=4 2x^2+3y^2=12

(x + y - 8) /( 2 ) = ( x + 2y - 14 ) /( 3) = ( 3x + y - 12)/( 11)

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

Using matrices,solve the following system of linear equations: 3x-2y+3z=8;2x+y-z=1;4x-3y+2z=4

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

The following steps are involved in finding the value of x.y, if (3x + 4y)/(2x + 5y) = (4)/(3). Arrange them in sequential order from the first to the last. (A) 9x + 12 y = 8x + 20y (B) Given, (3x + 4y)/(2x + 5y) = (4)/(3) (C) (x)/(y) = 8 rArr x:y = 8:1 (D) (3x + 4y)3 = (2x + 5y)4 (E) x = 8y