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Q 6 Ex-3.7 | STD 6 MATHS | Chap-3: PLAYI...

Q 6 Ex-3.7 | STD 6 MATHS | Chap-3: PLAYING WITH NUMBERS| PART-34 | NCERT |

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Class 10 Exercise 10.2 Question 1 | CBSE Class 10 Ex -10.2 Q1 | NCERT | Class 10 Maths Chapter 10

Add : 6- 3a + b , a - 7-6b and 3b + 2- a.

If -3+5i is a root of the equation x^2+p x+q=0 , then the ordered pair (p ,q) is (p ,q in R) (-6,34) (b) (6,34) 34 ,-6) (d) 34 ,6)

If 10a=6b+7 and a-6b=34 , then what is the value of (-1)/(3)a ?