`[((-2)/(-3))times(1)/(5)]times((-2)/(7))=((-2)/(-3))times[(1)/(5)times((-2)/(7))]`

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))

(4)/(5)times((-2)/(3))-(2)/(5)times(1)/(3)+(3)/(5)times(4)/(5)=

(2)/(5)times((-3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

(2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

((-4)/(3))times(1)/(2)+((-4)/(3))times((-7)/(5))

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

((1)/(3)times(2)/(9))/((1)/(3)times(1)/(5)+(1)/(3)times(1)/(3)+(1)/(3)times(2)/(9))

-(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(7)/(6)

Using appropriate properties find. (i) -(2)/(3)times(3)/(5)+(5)/(2)-(3)/(5)times(1)/(6) (ii) (2)/(5)times(-(3)/(7))-(1)/(6)times(3)/(2)+(1)/(14)times(2)/(5)

((2)/(7))^(3)times((1)/(2))^(3)