`(sqrt5 sqrt4) /( sqrt5 - sqrt4)`

The value of { 1/(sqrt6 - sqrt5) - 1/(sqrt5 - sqrt4) + 1/(sqrt4 - sqrt3) - 1/(sqrt3 - sqrt2) + 1/(sqrt2 - 1)} is :

Prove that sin 27^circ = 1/4 (sqrt(5 + sqrt5) - sqrt(3 - sqrt5)) .

Prove that sin 9^circ = 1/4 (sqrt(3 + sqrt5) - sqrt(5 - sqrt5)) .

If a= (sqrt(5) + sqrt(2))/(sqrt(5) -sqrt(2)) and b = (sqrt(5)-sqrt(2))/(sqrt(5)+sqrt(2)) show that 3a^(2) + 4ab -3b^(2) = 4 +(56)/(3) sqrt(10)

Arrange the following in descending order sqrt3 - sqrt2, sqrt4 - sqrt3 , sqrt5 - sqrt4 , sqrt2 - 1.

Show that (sqrt5+sqrt3)/(sqrt5-sqrt3)-(sqrt5-sqrt3)/(sqrt5+sqrt3)=2sqrt15

What is (sqrt5+sqrt3)/(sqrt5-sqrt3)+(sqrt5-sqrt3)/(sqrt5+sqrt3) equal to

The value of [1/(sqrt9-sqrt8)]-[1/(sqrt8-sqrt7)]+[1/(sqrt7-sqrt6)]-[1/(sqrt6-sqrt5)]+[1/(sqrt5-sqrt4)] is A)6 B)5 C)-7 D)-6