`Log_9(27)=2x+3` how to solve this

If 3log_(2)x+log_(2)27=3 then the value of x is

If log_(3)27.log_x7=log_(27)x.log_(7)3 , the least value of x is

If (log_(3)(a))^(3)+(log_(b)(3))^(3)+9log_(b)(a)=27 Then the value of a is

If 3log_((3x^(2)))27-2log_((3x))9=0 , then what is the value of x?

Suppose that a and b are positive real numbers such that log_(27)a+log_(9)(b)=(7)/(2) and log_(27)b+log_(9)a=(2)/(3). Then the value of the ab equals

If 2x^(log_(4)3)+3^(log_(4)x)= 27 , then x is equal to

If "log"_(3) x + "log"_(9)x^(2) + "log"_(27)x^(3) = 9 , then x =

Suppose that a and b are positive real numbers such that log_(27) a + log_(9) b = 7/2 " and " log_(27) b + log_(9) a = 2/3 . Find the value of the ab.

Evaluate int x^(2)log (1-x^(2))dx , and hence prove that (1)/(1.5)+(1)/(2.7)+(1)/(3.9)+...=2/3 log 2 - 8/9 .