`∆abc ~= ∆ pqr . A (∆abc) : A (∆pqr) = 16 : 25` . if bc = 2 cm then find QR ​

(B) Solve any four of the following subquestions : Delta ABC ~ Delta PQR, A (Delta ABC) = 9 cm^(2) and A ( DeltaPQR) = 16 cm^(2) . If BC = 2.1 cm then find the length of segment QR .

In a triangle PQR, PQ = 20 cm and PR = 6 cm, the side QR is :

If   Delta ABC ~ Delta PQR   , perimeter of Delta ABC = 32 cm, perimeter of Delta PQR = 48 cm and PR = 6 cm, then find the length of AC.

If triangle ABC is similar to triangle PQR , Perimeter of triangle ABC = 30 cm , Perimeter of triangle = 45 cm , PR = 9 cm then find AC.

The perimeters of two similar triangles ABC and PQR are 60 cm and 36 cm respectively. If PQ = 9 cm, then find the length of AB.

triangle ABC ~ triangle QRP and AB = 8 cm , BC = 12 cm and AC = 6 cm. If ar(triangle ABC) :ar(triangle PQR) = 16: 25, then RQ is equal to: triangle ABC ~ triangle QRP है और PQ = 6cm, QR = 8cm तथा PR = 10cm है । यदि ar(triangle ABC) : ar (triangle PQR) = 16:25 है, तो RQ ज्ञात करें |

Delta ABC ~ Delta QRP . If the ratio of the area of Delta ABC to the area of Delta PQR is 576 : 169. AB =10 cm, AC = 12 cm and BC =13 cm. then the length of PR (in cm) is equal to: