`(6a^2- 7ab + 2b^2) - (3a^2 + b^2) =`

Find the sum of the expresson - 15 a ^(2) + 3 ab - 6b ^(2) a ^(2) - 5 ab + 11 b ^(2) , - 7a ^(2)- 18 ab - 13 b ^(2) and 26 a ^(2) - 16 ab - 7b ^(2).

Subtract: 5a^(2) - 7ab + 5b^(2) "from" 3ab - 2a^(2) - 2b^(2)

what must be subtracted from 3a^(2) - 6ab - 3b^(2) - 1 to get 4a^(2) - 7ab - 4b^(2) + 1 ?

If (a^2 + b^2)^3 = (a^3 + b^3)^2 and ab != 0 then (a/b + b/a)^6 is equal to :

The product (a+b)(a-b)(a^(2)-ab+b^(2))(a^(2)+ab+b^(2)) is equal to: a^(6)+b^(6)(b)a^(6)-b^(6)(c)a^(3)-b^(3)(d)a^(3)+b^(3)