If `p(x)=x^2-1` then find `p(-1)​`?

If p(x)=x^2-1 then find the values of p(x) when x=1,-1

If P(x)= x^4+1 , then find P(2)-P(-2).

If p(x)=x^(3)-1 ,then find the value of p(-1)+p(1)

If P={:[(-1,0),(2,-1)]:}andf(x)=x^(2)-2x+2 , then find f(P).

(x^(2)+x+1)p(x-1)=(x^(2)-x+1)p(x) If p(1)=3 then find int_(-2)^(1)(dx)/(p(x)+x)

if p(x)=3x^(2)+2x-2 then find the value of p(3)-p(-1)+p((1)/(2))

If P(x) = x^3 - 1 , then find the value of P(1) + P( -1 )

If p(x)=x^(2)-3x+2" then "p(1)+p(-1)-p(0) is ..............

If p(x)=x^(3)-3x^(2)+2x , find p (0) , p(1) , p(2). What do you conclude?

If HCF and LCM of two polynomial P(x) & Q(x) is (a+1) and a^(3) + a^(2)-a-1 respectively if P(x)= (a^(2)-1) , find Q(x)= ?