`3 tan 28 × tan 62 - (sec 36)/( cosec 54) + (sin 28)/ (cos 62)`

Prove that (tan A + sec A-1) / (tan A-sec A + 1) = (1 + sin) / (cos A)

(tan A + sec A-1) / (tan A-sec A + 1) = (1 + sin A) / (cos A)

Prove that (i) (tan A+ sin A)/(tan A- sin A)= (sec A+1)/(sec A-1) (ii) (cot A- cos A)/(cot A+ cos A)= ("cosec" A-1)/("cosec" A+1)

Without using trigonometric tables, find the value of : (2)/(3) ((sec 56^(@))/( cosec 34^(@))) - 2 cos^(2) 20^(@) + (1)/(2) cot 28^(@) cot 35^(@) cot 45^(@) cot 62^(@) cot 55^(@) - 2 cos ^(2) 70^(@)

(sec A (sec A + tan A)(1-sin A))/ ((cosec^2 A-1)sin^2 A) is equal to: (sec A (sec A + tan A)(1-sin A))/ ((cosec^2 A-1)sin^2 A) का मान क्या होगा ?

(cos 28^(@))/(sin 62^@)=?

(tan A+cot A)=(sec A*csc A)

IF 2 tan ^(-1) (cos x) =tan ^(-1) (2 "cosec"x) then sin x cos x=