A particle is released from rest from a height. Find the distance it falls through in at `T_1 = 1` second `T_2 = 2` second and `T_3 = 3` second

A particle is released from rest from a tower of height 3h. The ratio of time intervals for fall of equal height h i.e. t_(1):t_(2):t_(3) is :

A ball released from rest from the roof of a building of height 45 m at t = 0. Find the height of ball from ground at t = 2s.

A ball is released from the top of a tower of height h metre. It takes T second to reach the ground. What is the position of the ball in T/3 second?

A particle starts from the origin and moves along a stright line If the velocity of the particle at time t seconds 10t cm/s then find the distance traversed during fist seconds after the start.

A particle is falling freely under gravity. In first t second it covers distance x_1 and in the next t second, it covers distance x_2, then t is given by

The position of a particle moving rectilinearly is given by x = t^3 - 3 t^2 - 10 . Find the distance travelled by the particle in the first 4 seconds starting from t = 0 .