A wheel starting from rest acquires and angular velocity of 10 radian per second in to 2 seconds. the moment of inertia of the wheel is 0.4 `kg m^2` calculate the torque acting on it

A wheel starts from rest and acquires an angular velocity of 60 rad//s in half a minute . Then its angular acceleration is

A fly wheel is making 300 rpm. Its angular velocity in radian per second is .

A wheel starting with angular velocity of 10 radian/sec acquires angular velocity of 100 radian/sec in 15 seconds. If moment of inertia is 10kg-m^(2) , then applied torque (in newton-metre) is

A wheel rotating at an angular speed of 20 rad/s ils brought to rest by a constant trouque in 4.0 secons. If the moiment of inertia of the wheel about the axis of rotation is 0.20 kg-m^2 find the work done by the torque in the first two seconds.

Starting from rest the fly wheel of a motor attains an angular velocity of 60 rad//sec in 5 seconds. The angular acceleration obtained is

A wheel starts from rest and attains an angular velocity of 20 radian/s after being uniformly accelerated for 10 s. The total angle in radian through which it has turned in 10 second is

A wheel is at rest. Its angular velocity increases uniformly and becomes 80 radian per second after 5 second. The total angular displacement is :-

A wheel having a diameter of 3 m starts from rest and accelerates uniformly to an angular velocity of 210 r.p.m. in 5 seconds. Angular acceleration of the wheel is

A wheel starts rotating at 10 rad/sec and attains the angular velocity of 100 rad/sec in 15 seconds. What is the angular acceleration in rad/ sec^(2) ?