`[Cr (Cl)_6]^3` and `[Cr (CN)_6]^3` both have same paramagnetic behaviour and shape. Why?

[Fe(CN)_6]^(3-) & [Cr(CN)_6]^(3-) . Find hybridisation & magnetic character

[Cr(NH_3)_6]^(3+) ion is:

Assertion: [Mn(CN)_6]^(3-),[Fe(CN)_6]^(3-) and [Co(CN)_6]^(3-) have d^2sp^3 hybridisation Reason: [MnCl_6]^(3-) and [FeCl_6]^(3-) are paramagnetic with unpaired electrons 4 and 5 respectively

The complexes [Co(NH_3)_6] [Cr(CN)_6] and [Cr(NH_3)_6] [Co(CN)_6] are the examples of which type of isomerism ?

The comlexes [Co(NH_3)_6] [Cr(CN)_6] and [Cr(NH_3)_6] [Co(CN)_6] are the examples of which type of isomerism?

[Ni(CN)_(4)]^(2-) is diamagnetic while [Cr(NH_(3))_(6)]^(3+) is paramagnetic. Explain.

[Cr(NH_3)_6]^(3+) is paramagnetic while [Ni(CN)_4]^(2-) is diamagnetic. Explain why?