Magnesium loss electrons successively to form `Mg^+, Mg^2+,Mg^3+` ions.Which step will have the highest ionisation energy and why

Out of Na and Mg which has higher second ionisation energy?

The number of electrons needed to reduce 3gm of Mg^(2+) to Mg are

Number of electrons required to deposit one mole of Mg^(2+) ions is

a. Among Cu^(o+) , Cu^(2+) and Cu which is the largest in size and why? b. Which element in periodic table has the highest IE (ionisation energy)? c. Which element, Mg or Al , is more metallic and why?

The hydration energy of Mg^(2+) is-

The second ionisation energies are higher than the first ionisation energies. This is mainly due to the fact that after the removal of the first electrons, the atom changes inot mono valent position ion. In the ion, the number of electrons decreases but the nuclear charge remains the same. As a result of this, the remaining electrons are held more tightly by the nucleus and it becomes difficult to remove the second electron . Therefore, the value of second ionisation energy . (IE_(2)) , is greater than that of the first ionisation energy (IE_(1)) . Similarly third ionisation energy (IE_(3)) is greater than that of second IE_(2) . IE_(1) and IE_(2) of Mg metal are 178 and 348 kcal/mol respectively . The energy required for the given reaction is : Mg(g)rarr Mg^(+2)(G)+2e^(-)

Two elements x & y have more ionisation energy than Mg. z have less ionisation energy than Mg. x,y,z respectively

The hydration energy of Mg^(2+) ions is lesser than that of: