std 7 science ch 13 swadhyay pothi ,dhoran 7 vigyan swadhyay pothi , dhoran 7 swadhyay pothi ch 13

Consider the point A= (3, 4), B(7, 13) . If 'P' be a point on the line y = x such that PA +PB is minimum then coordinates of P is (A) (13/7,13,7) (B) (23/7,23/7) (C) (31/7,31/7) (D) (33/7,33/7)

Divide the sum of -13/5 and 12/7 by the product of -13/7 and -1/2

Solve for x : 12x -7 = 7x - 13

Average of 13 numbersis 40. If average of first 7 numbers be 42 and that of last 7 be 35,find the 7th number.

Find the A.M.between: 7 and 13

The heat released in neutralisation of HCI and NaOH is 13.7 kcal/mol, the heat released on neutralisation of NaOH with CH_(3)COOH is 3.7 kcal/mol. The Delta H^(@) of ionsiation of CH_(3)COOH is

The common multiples of 7 and 13:

heat of neutralisation of HCl against NaOH is 13.7 kcal eq^(-1) what will be the ionisation energy of CH_(3)COOH in kcal mol^(-1) if its heat of neutralisation is 11.7 kcal eq^(-1) .

If a=7 and a_(13)=35, then find d and S_(13)