Vapour Pressure Of Solution || Raoult's Law || NEET || NCERT || JEE

A solution that obeys Raoult’s law is:

For a dilute solution, Raoult's low states that :

Give any two limitations of Raoult's law.

State Raoult's law. Explain from it why the vapour pressure of a solution is always less than that of a pure solvent.

The vapour pressure of acetone at 298 K is 40 mm of Hg . Its mole fraction in a solution with alcohol is 0.80 . What is its vapour pressure in solution if the mixture obey Raoult's law?

Moment of Inertia | IIT JEE | NEET | CBSE

At 300 K, the vapour pressure of an ideal solution containing 1 mole of A and 3 moles of B is 500 mm Hg. At the same temperature, 2 moles of B are added to this solution. The vapour pressure of solution increases by 10% of the original vapour pressure. Correct statements about the vapour pressure are

The vapour pressure of a solution having solid as solute and liquid as solvent is:

The vapour pressure of pure benzene is 639.7 mm Hg and the vapour pressure of solution of a solute in benzene at the temperature is 631.9 mm Hg . Calculate the molality of the solution.

Answer the question (given below) which are based on the following diagra. Consider some facts about the above phase diagram : Vapour pressure diagram for real solutions of two liquids A and B that exhibit a positive deviation from Raoult's law. The vapour pressure of both A and B are greater than predicted by Raoult's law. The dashed lines lines represented the plots for ideal solutions. Total vapour pressure of mixture of 1 mol of volatile component A(P_(A)^(@)=100 mmHg) and 3 mol of volatile component B(P_(B)^(@)=60 mmHg) is 75 mm . For such case: