Vapour Pressure Of Solid in liquid || NCERT || NEET || JEE

Vapour pressure of a liquid depends on

Define vapour pressure of a liquid.

Vapour pressure of a liquid decreases with

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour pressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

When vapour condenses into liquid

Vapour pressure of mixture of liquid A and liquid B at 70^(@)C is given by P_(T)=180X_(B)+90 (in mm) . Where X_(B) is the mole fraction of B, in the liquid mixture. Calculate (a) Vapour pressure of pure A and pure B (b) Vapour pressure of mixture of A and B by mixing 4 g and 12 g B. (If molar mass of A and B are 2 g and 3 g respectively) (c ) From (b) ratio of moles of A and B in vapour at 70^(@)C

The vapour pressure of a certain pure liquid A at 298 K is 40 mbar. When a solution of B is prepared in A at the same temperature, the vapour pressure is found to be 32 mbar. The mole fraction of A in the solution is

Vapour pressure of a pure liquid does not depend upon

The vapour pressure of a given liquid will decrease if :

The vapour pressure of a given liquid will increase if